1. (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 ml. of an HCl solution. The molarity of th HCl solution is (show your work): (Points: 5)

molarity = moles solute/liters solution 0.25 M = moles NaOH/0,035 L moles NaOH=0.00875 moles NaOH

2. (TCO 1) How many mL are in 3.5 pints? Show your work. (Points: 5)

3.5 pints is equivalent to 1656.116

1 pint=473.176 mi 3.5 pints 473.176mL1656.116m

3. (TCO 3) What is the name of the following compound: Zn,P.? (Points: 5)

It's Zinc Phosphide

4. (TCO 3) What is the name of the following compound: AgNO,? (Points: 5)

Silver nitrate


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