How many aluminum atoms are there in 52 g of Al2S3 4.2 x 10^23 1.6 x 10^21 2.1 x 10^23 1.1 x 10^21 6.3 x 10^23 wrong 52g Al2S3 = 1 mol Al2S3 = 2 mol Al = 6.02 x 10^23 Al = 4.2 x 10^23 Al atoms 150g Al2S3 1 mol Al2S3 1 mol Al 2. A 15-g sample of lithium is reacted with 15 g of fluorine to form lithium fluoride: 2Li + F2 ==> 2[LiF]. After the reaction is complete, what will be present? a) 2.16 mol lithium fluoride only b) 0.789 mol lithium fluoride only c) 2.16 mol lithium fluoride and 0.395 mol fluorine d) 0.789 mol lithium fluoride and 1.37 mol lithium e) none of these 3. What is the mass percent of carbon in the compound c6h6o2 a) 5.5% b) 70.9% c) 65.5% d) 29.1% e) 14.3% 4. How many aluminum atoms are there in 52 g of Al2S3 4.2 x 10^23 1.6 x 10^21 2.1 x 10^23 1.1 x 10^21 6.3 x 10^23 wrong 52g Al2S3 = 1 mol Al2S3 = 2 mol Al = 6.02 x 10^23 Al = 4.2 x 10^23 Al atoms 150g Al2S3 1 mol Al2S3 1 mol 5. if 48.8g of o2 is mixed with 48.8g of h2 and the mixture is ignited, what is the maximum mass of water that may be produced? a) 439 g b) 54.9 g correct c) 48.8 g d) e) 2H2 + O2 -> 2H2O 48.8g O2 = 1 mol O2 = 2 mol H2O = 3.05 mol H2O 32g O2 1 mol O2 48.8g H2 = 1 mol H2 = 2 mol H2O = 24.4 mol H2O 2 g H2 2 mol A2 3.05 mol H2O = 18 g H2O = 59.9 g H2O 1 mol 6. 2Al(s) + 6HCl(aq) 2AlCl3 (aq) + 3H2 (g) According to the equation above, how many grams of aluminum are needed to react with 3.83 mol of hydrochloric acid? A] 310 g B] 46.6 g C] 34.4 g correct D] 3.83 g E] 103.3 g 3.83 mol HCl = 2 mol Al = 27 g Al = 34.4g 6 mol HCl 1 mol Al
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