Solution a = 2t - 6 dv = a dt L v 0 dv = L t 0 (2t - 6) dt v = t 2 - 6t ds = v dt L s 0 ds = L t 0 (t2 - 6t) dt s = t 3 3 - 3t2 When t = 6 s, v = 0 Ans. When t = 11 s, s = 80.7 m Ans. Starting from rest, a particle moving in a straight line has an acceleration of a = (2t - 6) m>s2, where t is in seconds. What is the particle’s velocity when t = 6 s, and what is its position when t = 11 s? Ans: v = 0 s = 80.7 m 1 1
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