SOLUTION (1.1) We have 3 2 A 50 75 3.75(10 ) m ! = " = , 90 40 50 o o o ! = " = , and ! x = P A. Equations (1.8), with o ! = 50 : x P o x 700(10 ) x cos 50 0.413 110.18 3 2 ! ' = = ! = ! = or P = 6.35 kN x P o o x y x 560(10 ) sin 50 cos50 0.492 131.2 3 " ' ' = ! = ! = Solving P = 4.27 kN = Pall ______________________________________________________________________________________ SOLUTION (1.2) Normal stress is MPa A P x 50 0.05 0.05 125(10 ) 3 " = = ! = ( a ) Equations (1.11), with 90 70 20 o o o ! = " = : MPa o x 50cos 20 44.15 2 ! ' = = MPa o o " x' y' = !50sin 20 cos 20 = !16.08 MPa o o y 50cos (20 90 ) 5.849 2 ! ' = + = ( b ) Equations (1.11), with o ! = 45 : MPa o x 50cos 45 25 2 ! ' = = MPa o o " x' y' = !50sin 45 cos 45 = !25 MPa o o y 50cos (45 90 ) 25