1. What mass of NaOH is needed to prepare 800.0 mL of a solution having a pH of 12.56? (6 points) pH = 12.56. pOH = 14 – 12.56 = 1.44 Therefore, [OH- ] = 10-1.44 = 3.6 x 10-2 M Since NaOH is a strong base, conc. of NaOH = conc. of [OH- ] = 3.6 x 10-2 M moles of NaOH = molarity * volume (in L) = 3.6 x 10-2 * 0.8 L = 2.88 x 10-2 moles NaOH grams = moles * molar mass of NaOH = 1.15 grams NaOH 2. Carboxylic acids (i.e compounds that contain the –COOH group) are examples of organic acids and amines (-NH2 groups) are examples of organic bases. For the following compound (shown below) draw the structures of the conjugate base and the conjugate acid: (6 points)